Please help.The difference between of two numbers is 49. one half of the larger number plus one seventh of the smaller num?
Let x be the bigger number and y be the smaller number.
x - y = 49
1/2(x) + 1/7(y) = 56
In the first equation, we can rearrange:
x - y = 49
x = 49 + y
Then, using this, we can subsitute 49 + y into the second equation for x and solve:
1/2(49 + y) + 1/7(y) = 56
49+y + 2/7(y) = 112
343 + 7y + 2y = 784
9y + 343 = 784
9y = 441
y = 49
Since y = 49, x - y = 49 becomes x - 49 = 49, and x is 98.The difference between of two numbers is 49. one half of the larger number plus one seventh of the smaller num?
Bigger Number = x, Smaller Number =y.
X-Y=49 - (1)
1/2X+1/7Y=56 - (2)
From (2) X=112-2/7Y
Sub into (1):
112-2/7Y-Y=49
9/7Y=63
Y=49
X=98
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