114 - 126
evenses is divisible by 2 (that took care of 7 of 13).
it IS natural to assume that the sequence starts and ends with even numbers.
another 2 (of remaining 6) is divisible by 3 (but not 6).
because (floor)[13/3] = 4, with 2 already being evenses. so just 2 of 3-divisible odds.
and 2 assured members of sequence is divisible by 5 (with 1 in reserve). at least 1 of 4 left is divisible by 5.
the {big prime}*{big prime} are
7 * 17 = 119 and
11 * 11 = 121
answer = 114The integers from 1 to 200 contain a sequence of 13 consecutive composite numbers. What is the smallest number
look at list of prime numbers
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